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Free 120 usmle step 1 answers
Free 120 usmle step 1 answers











If the threshold is lowered to 2.0 ng/mL, some patients who were previously considered negative will be considered positive. Pulmonary function testing classically reveals decreased FEV1:FVC ratio ( 4.1 ng/mL were considered a positive result. Breathing through pursed lips is performed in order to prevent expiratory alveolar collapse (auto-PEEP). Over time patients may develop severe hyperinflation and a barrel chest. Patients may experience shortness of breath and dyspnea on exertion/at rest.

free 120 usmle step 1 answers

This causes increased alveolar collapse on expiration, air trapping and hyperinflation, impaired ventilation, and increased dead space, leading to hypoxemia and hypercapnia.

  • E- Emphysema is a component of chronic obstructive pulmonary disease characterized by loss/damage of alveolar elastin and lung parenchyma due to a protease/antiprotease imbalance.
  • This patient is at risk for the development of this condition based on her history of type 2 diabetes mellitus. A vaginal smear reveals the presence of normal vaginal epithelium and pseudohyphae, confirming the diagnosis of vaginal candidiasis. Physical exam reveals edematous, erythematous vaginal mucosa with white discharge, suggestive of a candidal infection.
  • A- This patient has vaginal pain, pruritus, and dyspareunia.
  • Based on this, 50% of individuals will have leukocyte counts greater than 7500 and 50% will have leukocyte counts less than 7500. In this example, the mean leukocyte count is 7500 cells/mm3.
  • D- For a normal distribution of data, mean (average) is the most reliable measure of central tendency.
  • Severe acute kidney injury can be lethal if not properly managed, although the question states that this patient’s death was secondary to a cardiac arrhythmia, likely due to damage sustained from ischemia during cardiac arrest. This is not uncommon after several weeks.

    #FREE 120 USMLE STEP 1 ANSWERS FULL#

    Most patients with ATN will experience tubular re-epithelialization and spontaneous full recovery. Two weeks after his initial cardiac arrest, the oliguria and azotemia resolved, representing the recovery of acute tubular necrosis.

    free 120 usmle step 1 answers

    The diagnosis of ATN is supported by his oliguria, azotemia, and urinary granular casts. This was most likely due to severe renal ischemia due to impaired cardiac output.

  • E- Six weeks ago, this patient developed acute renal failure and ischemia-induced acute tubular necrosis (ATN) in the setting of cardiac arrest due to underlying coronary artery disease.
  • free 120 usmle step 1 answers

    The lower end of the confidence interval is thus 130 – (1.96 x 5), which equals 120.2, and the higher end of the confidence interval is 130 + (1.96 x 5) which equals 139.8.

  • B- The formula for a 95% confidence interval for data that follow a normal distribution is x̅ +/- (1.96 x Standard Error), where x̅ is the mean.










  • Free 120 usmle step 1 answers